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2x^2=500^2
We move all terms to the left:
2x^2-(500^2)=0
We add all the numbers together, and all the variables
2x^2-250000=0
a = 2; b = 0; c = -250000;
Δ = b2-4ac
Δ = 02-4·2·(-250000)
Δ = 2000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2000000}=\sqrt{1000000*2}=\sqrt{1000000}*\sqrt{2}=1000\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1000\sqrt{2}}{2*2}=\frac{0-1000\sqrt{2}}{4} =-\frac{1000\sqrt{2}}{4} =-250\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1000\sqrt{2}}{2*2}=\frac{0+1000\sqrt{2}}{4} =\frac{1000\sqrt{2}}{4} =250\sqrt{2} $
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